My Pker's Calculator {Made in visual basic}

[my pker pure]

I was bored, so i started on a new project of a calculator... It originally started out as a paint project like as in windows paint/drawing app but i decided to go for something a bit easier. (Hope you enjoy all download links are below)


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[Spear]

Nice, I guess...

[Fellixombc]

Moved to the proper board...

[Joshua F]

Cept.. why make one, when Windows comes with a perfectly fine one?

[Shishir G]

Cept.. why make one, when Windows comes with a perfectly fine one?

dun be mean, i'm guessing he's still a beginner, so this is probably one of this new projects. It's a good start, nice job.

[samuraiblood2]

Instead of making buttons and a decently useless UI, you could've just parsed the input from the command line. Here's a simple calculator I just made in Java,


import java.util.Scanner;

public class CommandLineCalculator {

public static final String[] DELIMITERS = { "+", "-", "*", "/" };

public static void main(String[] args) {
Scanner in = new Scanner(System.in);
boolean doAgain = true;
do {
System.out.print("Problem: ");
String problem = in.nextLine();
String[] numbers = problem.split("\\s*[" + getDelimiter(problem) + "]\\s*");

if (numbers.length > 2) {
System.err.println("This program only supports simple problems.");
continue;
} else if (numbers.length < 2) {
System.err.println("You need at least two numbers in a problem.");
continue;
}

int first = 0;
int second = 0;
try {
first = Integer.parseInt(numbers[0]);
second = Integer.parseInt(numbers[1]);
} catch (NumberFormatException e) {
System.err.println("You must enter only numbers in place of values.");
continue;
}

int answer = 0;
if (getDelimiter(problem).equals("+")) {
answer = first + second;
} else if (getDelimiter(problem).equals("-")) {
answer = first - second;
} else if (getDelimiter(problem).equals("*")) {
answer = first * second;
} else if (getDelimiter(problem).equals("/")) {
answer = first / second;
}
System.out.println("Answer: " + answer);

System.out.print("Have another problem? (y/N) ");
doAgain = in.nextLine().equalsIgnoreCase("y");
} while (doAgain);
}

private static String getDelimiter(String problem) {
for (int i = 0; i < DELIMITERS.length; i++) {
if (problem.contains(DELIMITERS[i])) {
return DELIMITERS[i];
}
}
return null;
}
}

Programs output


Problem: 6*74
Answer: 444
Have another problem? (y/N) n

[my pker pure]

Thanks for the criticism but yeah i am new to this kind of programming so please dont flame

[Mish]

Awesome, goodjob :D

[my pker pure]

Awesome, goodjob :D

Thankyouu XD

[Malik]

Pretty cool, I would have no chance at making this myself ;)

[my pker pure]

New Project Is released - My Pker's Notepad - Only the registered members can see the link.

[Trey]

Cool. Now make one that parses infix to postfix using a stack and solves it, allowing for complex equations.

[samuraiblood2]

Cool. Now make one that parses infix to postfix using a stack and solves it, allowing for complex equations.

To much work, and I don't know enough about the postfix form.

[my pker pure]

I prefer to use visual basic it's abit more simple.

[Trey]

To much work, and I don't know enough about the postfix form.

Not as complex at it would seem, I prefer it over other methods of allowing equations like "(2 * (2 + (3 - 2))) * (8 + 2)" etc.

[Pie`]

This is below the beginner level. Realistically this is what, 2 lines of /actual/ code? The rest was just a simple drag & drop using the Visual Basic Studio IDE. He doesn't deserve recognition for this, he doesn't even deserve praise.

[samuraiblood2]

Not as complex at it would seem, I prefer it over other methods of allowing equations like "(2 * (2 + (3 - 2))) * (8 + 2)" etc.

But how would you handle equations like say, 55+5? In postfix that would turn to 555+ right?

[Trey]

But how would you handle equations like say, 55+5? In postfix that would turn to 555+ right?

That's why you insert spaces before and after all operators, and then parse it to postfix, ignoring solo spaces (in other words, if there already was a space before an operator now there will be 2, so we just ignore the second space). Any equation in postfix is solved in a single pass, which is why it is smart to convert infix to postfix so you can solve it in a single pass, since there is no order of operations in postfix.

[samuraiblood2]

That's why you insert spaces before and after all operators, and then parse it to postfix, ignoring solo spaces (in other words, if there already was a space before an operator now there will be 2, so we just ignore the second space). Any equation in postfix is solved in a single pass, which is why it is smart to convert infix to postfix so you can solve it in a single pass, since there is no order of operations in postfix.

Hmm, interesting, maybe ill mess around with it a little then. Is there a specific way to convert infix to postfix?

[Trey]

Hmm, interesting, maybe ill mess around with it a little then. Is there a specific way to convert infix to postfix?

Yup. I used these basic steps when I wrote a calculator a while ago. You'll have to tokenize your input rather than using a character by character method or else multiple digit numbers would be fucked. Precedence is order of operations.

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[Ramsin]

EasEasy but nice... good for starter.

[Sunni]

Saw a tutorial on this on youtube, copied?

[Skilled4u]

sunni so what if he followed a tutorial? ... he's just learning...

[my pker pure]

I didn't even follow a tutorial ROFL

[Sunni]

sunni so what if he followed a tutorial? ... he's just learning...

Didn't mean it like that, don't try to be smart, I was just wondering.

[admigo]

i can make a more advanced calculator.

[my pker pure]

i can make a more advanced calculator.

Nobody cares what you can and can't do noob.

[Charlie`]

haha nice!